2/(3x+3)-(X-1)/(9-9X^2)-3=0

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Solution for 2/(3x+3)-(X-1)/(9-9X^2)-3=0 equation: 



2/(3x+3)-(x-1)/(9-9x^2)-3=0



Domain of the equation: (9-9x^2)!=0

We move all terms containing x to the left, all other terms to the right

-9x^2!=-9

x^2!=-9/-9

x^2!=√1

x!=1

x∈R





Domain of the equation: (3x+3)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-3

x!=-3/3

x!=-1

x∈R



We calculate fractions


(-(x-1)*(3x+3))/((9-9x^2)*(3x+3))+(-18x^2+18)/((9-9x^2)*(3x+3))-3=0



We calculate terms in parentheses: +(-(x-1)*(3x+3))/((9-9x^2)*(3x+3)), so:

-(x-1)*(3x+3))/((9-9x^2)*(3x+3)

We multiply all the terms by the denominator


-(x-1)*(3x+3))

Back to the equation:

+(-(x-1)*(3x+3)))





We calculate terms in parentheses: +(-18x^2+18)/((9-9x^2)*(3x+3)), so:

-18x^2+18)/((9-9x^2)*(3x+3)

We multiply all the terms by the denominator


-18x^2*((9-9x^2)*(3x+3)+18)

Back to the equation:

+(-18x^2*((9-9x^2)*(3x+3)+18))

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